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ioda
4 years ago
11

A wave has a wavelength of 0.05 m and a wave speed of 10 m/s. What is the frequency of the wave

Physics
1 answer:
harkovskaia [24]4 years ago
4 0
Divide 10 by .05 and that is your answer
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A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T
Dennis_Churaev [7]

Answer:

The value of x is  x = 0.1955\ m

The value of the velocity at the top is  v_{top} = 2.25 \ m/s

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

     The mass of the block is m_b = 0.490kg

      The distance of compression is x

      The force constant is k = 450 N/m

      The radius of the circular track is R =1.00m

       The speed at the bottom of the track is v_A = 13.4 \ m/s

        The frictional force experienced is F_f = 7.00 \ N

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy  of the block . So,

          PE \ of \ spring = KE \ of  \ block

mathematically i.e

        \frac{1}{2}k x^2  = \frac{1}{2} m_bv^2_A

       0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2

Making x the subject of the formula

           x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }

              = 0.1955\ m

The average workdone by friction is  W_f = F_f * \pi

Here \pi is \ the\  net\ displacement

                                         W_f = 7 * 3.142

                                               = 21.99 J

The kinetic energy at the bottom is

                                     KE = \frac{1}{2} * 0.490 * 13.4^2

                                            = 43.99 \ N

The potential energy gained at the top of the circle is

                              PE = m_bgh

Here h  is the height which is equal to d(diameter)  = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity = 9.8m/s^2

Now substituting values

                       PE = 0.490 * 9.8 *2

                             =9.604 J

Since energy is can not be created nor destroyed but transformed  according to first law of thermodynamics

                  KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}

                      43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]

                        12.369= [2.45* v_{top} ^2]

                            v_{top} =\sqrt{\frac{12.369}{2.45} }

                                  = 2.25 \ m/s

                                     

                                 

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