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hjlf
2 years ago
5

Timbre describes the sound’s _____. pitch loudness tone quality

Physics
2 answers:
Bumek [7]2 years ago
7 0

Answer:

A) pitch

Explanation:

I did band and also g*ogled it to check :)

If it isn't A, however, it is C

Hope this helps :D

GrogVix [38]2 years ago
3 0

Answer:

loudness

Explanation:

allow the ear to distinguish sounds which have the same pitch and loudnes

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ASK YOUR TEACHER A baseball with a mass of 146 g is thrown horizontally with a speed of 40.6 m/s (91 mi/h) at a bat. The ball is
RideAnS [48]

Answer:

Explanation:

mass of the ball = 146 g = 146 / 1000 = 0.146 kg

initial speed of the ball = 40.6 m/s

final speed of the ball = - 45.1 m/s

time of impact = 1.05 ms = 1.05 / 1000 = 0.00105 s

impulse, Ft = change in momentum = mv - mu = m (v-u)

F = m (v - u) / t = 0.146 kg ( -45.1 -40.6) / 0.00105 s = -11916.4 N

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3 years ago
What is induced current​
Brrunno [24]

Answer:

A current can be induced in a conducting loop if it is exposed to a changing magnetic field. ... In other words, if the applied magnetic field is increasing, the current in the wire will flow in such a way that the magnetic field that it generates around the wire will decrease the applied magnetic field.

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3 years ago
Please help
JulsSmile [24]

Answer:

D

Explanation:

because it is the only one that has something to do with heat keyword would be boiling

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3 years ago
A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force th
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Answer:

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3 years ago
A baseball is thrown at an angle of 20° relative to the ground at a speed of 25 m/s if the ball was caught 50 m from the thrower
scoray [572]

Answer:

2.1 s

Explanation:

The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

d = 50 m

And that the initial speed of the ball is

u=25 m/s

at an angle of

\theta=20^{\circ}

So, the horizontal speed of the ball (which is constant during the entire motion) is

u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s

which is the time the ball spent in air.

8 0
3 years ago
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