All categories

1 year ago

Timbre describes the sound’s _____. pitch loudness tone quality

Physics

2 answers:

Bumek [7]1 year ago

7 0

Answer:

A) pitch

Explanation:

I did band and also g*ogled it to check :)

If it isn't A, however, it is C

Hope this helps :D

GrogVix [38]1 year ago

3 0

Answer:

loudness

Explanation:

allow the ear to distinguish sounds which have the same pitch and loudnes

You might be interested in

A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional prob

AlladinOne [14]

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red $=\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}$

$P=\frac{^{4}C_2}{^{6}C_2}$

$P=\frac{2}{5}$

Required Probability $=1-\frac{2}{5}=\frac{3}{5}$

7 0

3 years ago

What can be concluded about the atom from knowing that oxygen-18 has an atomic number of 8? A) An oxygen atom that includes 8 ba

anyanavicka [17]

B)

If it is known that the atomic number is 8, we know that the electrons are also 8. Since the atomic mass (O18) is 18, the neutrons are 18-8=10. Option B is the correct answer.

Hope I helped :)

4 0

2 years ago

Read 2 more answers

You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica

Pani-rosa [81]

Answer:

Length = 2.92 m

Diameter = 0.11 mm

Explanation:

We have $m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A}$ , where:

$l$ is the length

$m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3$

We divide the first equation by the second equation to get:

$\frac{m}{R} = \frac{d A^2}{\rho}$

$A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8} \ m^2$