Answer:
The velocity of wind with respect to cyclist is .
Explanation:
speed of cyclist = 12 km/h east
speed of wind = 5 km/h south west
Write the speeds in the vector form
The velocity of wind with respect to cyclist is
A man with a mass of 60 kg walks up two flights of stairs in going from the first floor to the third floor (10 meters). Calculat
2 answers:
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The body moves at a velocity of 1.62m/s after the bullet emerges.
<h3>Given:</h3>Mass of bullet, = 22g
= 0.022 kg
Mass of the block, = 1.9 kg
Velocity of bullet , = 265 m/s
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
After penetration;
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
∴ Momentum before = Momentum after
Substitute the given parameters into the formula as shown:
Therefore, It moves with a velocity of 1.62 m/s.
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