Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
<span>The right information from the figure is:
AU = 20x + 108,
UB = 273,
BC = 703,
UV = 444,
AV = 372 and
AC = 589
The similarity of the two triangles leads to:
[AB] / [AC] = [AU] / [AV]
[AB] = [AU] + [UB] = 20x + 108 + 273 = 20x + 381
=> (20x + 381) / (589) = (20x + 108) / 372
Now you can solve for x.
(372)(20x + 381) = (20x + 108)(589)
=> 7440x + 141732 = 11780x + 63612
=> 11780x - 7440x = 141732 - 63612
=> 4340x = 78120
=> x = 18
Answer: x = 18
</span>
Answer:
23,29,31,37,41,43,47,53,59,61 and 67.
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Step-by-step explanation:
Given
sin³ø cos ø + cos³ø sinø
= sin ø cos ø ( sin²ø + cos²ø)
= sinø cosø * 1
= sinø cosø
Hope it will help :)
Answer:
9,670
Step-by-step explanation:
8,219.5 ÷ 85% (0.85) = 9,670
