Answer:
a) A. The population must be normally distributed
b) P(X < 68.2) = 0.7967
c) P(X ≥ 65.6) = 0.3745
Step-by-step explanation:
a) The population is normally distributed having a mean (
) = 64 and a standard deviation (
) = 
b) P(X < 68.2)
First me need to calculate the z score (z). This is given by the equation:
but μ=64 and σ=19 and n=14,
and 
Therefore: 
From z table, P(X < 68.2) = P(z < 0.83) = 0.7967
P(X < 68.2) = 0.7967
c) P(X ≥ 65.6)
First me need to calculate the z score (z). This is given by the equation:
Therefore: 
From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745
P(X ≥ 65.6) = 0.3745
P(X < 68.2) = 0.7967
B. 10.1%
(2)(12)($88.18) ÷ [($1100)(18+1)]
(2,116.32) ÷ (20,900)
= 0.1012
= 10.1%
The first one is 400, the second on is 40, and the last one is 4 *I hope this help u
(3/5 + -1/4)/(7/10)
get a common denominator of 20
3/5 * 4/4 =12/20
-1/4 * 5/5 = -5/20
7/10 *2/2 = 17/20
replace
(12/20 - 5/20)/(14/20)
add the top
(7/20)/(14/20)
copy dot flip
7/20 * 20/14
7/14
1/2
Answer:
yupyup
Step-by-step explanation:
been having it for years now