3 years ago

NEED HELP NOW PLEASE

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

This might be the perpendicular bisector. I'm not 100% sure.

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Solve for X: d(−3+x)=kx+9

Andre45 [30]

Answer:

d(−3+x)=kx+9

-3d+d+x=kx+9

-2d+x=kx+9

-9 -9

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-2d-9+x=x

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4 years ago

0.5(8+3.2)/-0.1 + 3/(-2.7-6.3)

Nesterboy [21]

Answer:

= 167/3

Step-by-step explanation:

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3 years ago

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JulsSmile [24]

Answer:

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Step-by-step explanation:

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What property justify <br>if <1 = <2 and <2 = <3 then <1 = <3

krek1111 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the

Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

$\text{Distance}=\text{Speed}\times\text{Time}$

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

$\Rightarrow6x+18+6x = 162$

$\Rightarrow12x=162-18$

$\Rightarrow x=\frac{144}{12}\rightarrow x=12$

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be $x+3=12+3=15 \text{ mph}$

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3 years ago