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Zepler [3.9K]
3 years ago
13

Plz help In this equation, 2Mg + O2 → 2MgO, what is the coefficient of the oxygen molecule?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
8 0

The coefficient is 1

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A submarine fills a special storage area known as a ballast with water in order to increase its density. This allows it to dive
ollegr [7]

Answer:

the submarine floats after replacing the water with the compressed air

7 0
3 years ago
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2. If 1.204 X 1024 atoms of sodium is 20% of the total sodium atoms in sodium
GuDViN [60]

Answer:

584.2 g

Explanation:

Hello there!

In this case, since we know the 20% of the atoms correspond to sodium, we can compute the total atoms as shown below:

\frac{1.204 x10^{24}}{0.2}=6.02x10^{24}atoms

Which are also equal to 1 mol and the Avogadro's number of sodium chloride with a molar mass of 58.44 g/mol; thus, the grams of salt turn out to be:

6.02x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{58.44g}{1mol}\\\\=584.2g

Best regards!

3 0
3 years ago
Which of these are isotopes of each other? Boron-12, Carbon-12, Carbon-13, Nitrogen-13
Anika [276]
Carbon 13 I believe.
Never heard of an isotope for boron or nitrogen and I know Carbon 12 is the original form of carbon so.. Yeah
5 0
4 years ago
Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(
Semmy [17]

The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻  

<h3>What is Balanced Chemical Equation ?</h3>

The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.

Now write the equation for FeI₂

At cathode:

Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V

2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V

It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.

At anode:

2I⁻  → I₂ + 2e-    Eo = - 0.54 V

2H₂O  → O₂ + 4H⁺ + 4e⁻    Eo = -1.23 V

O₂ gas formed at anode.

Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

6 0
2 years ago
PLS help
viktelen [127]

Answer:

d . Sc2O5

Explanation:

Hello,

In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

Sc^{+5}_2O^{-2}_5

For that reason, the answer is d . Sc2O5

Best regards.

3 0
4 years ago
Read 2 more answers
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