All categories

3 years ago

What are the 3 laws of motion?

Chemistry

2 answers:

Rashid [163]3 years ago

7 0

Answer:

Below! ;)

Explanation:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Hope this helps!

Have a nice day!

If you find my answer helpful

Pls consider marking my answer as Brainliest! It would mean a lot!

laiz [17]3 years ago

4 0

Answer:

1.Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.

2.The relationship between an object's mass m, its acceleration a, and the applied force F is F = ma.

3.For every action there is an equal and opposite reaction.

Hope this Helps!

Pls Mark Brainliest I just need one more!

You might be interested in

Near the ceiling of a room air is warmer. The warm air rises because of

Amiraneli [1.4K]

Answer:

convection

Explanation:

heat will always rise

3 0

4 years ago

Read 2 more answers

Which atoms in the pair has the larger atomic radius ? Help please !!

Ne4ueva [31]

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

Explanation:

4 0

2 years ago

Read 2 more answers

"identify the part of the atom that most determines the chemical reactivity of the atom"

jeka94

Mostly the electrons will determine the reactivity

8 0

3 years ago

Consider the following reaction:

adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

2H₂O₂ ⟶ 2H₂O + O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

d[H₂O]/dt = 2d[O₂]/dt = 2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = 6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂

(a) Initial moles of H₂O₂

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }$

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

$\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }$

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

$\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}$

8 0

3 years ago

In most lewis dot structures of neutral compounds, carbon as the central atom will be bound to a maximum of how many atoms, nitr

Fittoniya [83]

The total number of elements that one particular element can bond to can be determined by simply drawing the Lewis structure of the element.

Place the chemical symbol
Then look at the group number = valence electrons
Distribute the valence electrons around the atom.

C = 4 bonds
N = 3 bonds
O = 2 bonds

7 0

4 years ago