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2 years ago

4. Andrew borrows $180 from his mom for

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

5 0

Answer:

180÷12

Step-by-step explanation:

the equation currently looks like

12n=180 basically

hint answers 5

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Please solve asap thanks

natima [27]

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

8 0

2 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

Help me, this is math and I need to this this extension.

Gnom [1K]

Applying pythagorean theorem:-

$\\ \sf\longmapsto 8^2-5^2=b^2$

$\\ \sf\longmapsto 64-25=b^2$

$\\ \sf\longmapsto b^2=39$

$\\ \sf\longmapsto b=\sqrt{39}$

$\\ \sf\longmapsto b=6.24$

5 0

2 years ago

Read 2 more answers

Can someone please help me on this question I will give brainliest

xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Surface Area of a Sphere: SA = 4πr²
Diameter: d = 2r

Step-by-step explanation:

Step 1: Define

SA = 23 in²

Step 2: Find r

Substitute [SAS]: 23 in² = 4πr²
Isolate r term: 23 in²/(4π) = r²
Isolate r: √[23 in²/(4π)] = r
Rewrite: r = √[23 in²/(4π)]
Evaluate: r = 1.35288 in

Step 3: Find d

Substitute [D]: d = 2(1.35288 in)
Multiply: d = 2.70576 in
Round: d ≈ 3 in

4 0

2 years ago

Determine the number of ways she can arrange her daily schedule.

natita [175]

Answer:

This can be found by using the permutations and combinations formuals.

Combinations being the C equation and Permutations being the P equation.

$P(n,r)=\frac{6!}{(6-6)!}=720$

Explanation:

A permutation is used for the list of data (where the order of the data matters) and the combination is used for a group of data (where the order of data doesn't matter).

3 0

2 years ago