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Leno4ka [110]
3 years ago
14

Need help ASAP with the correct answer!!!!!!

Mathematics
1 answer:
xenn [34]3 years ago
4 0
All of them except D have no real solutions
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Max joins a weight loss challenge beginning on January 1st. If his starting weight is 267 pounds and he loses weight at a rate o
Anna71 [15]
15.5 31 days in January and he loses .5 per day so the equation would be 31x.5 which equals 15.5
4 0
3 years ago
ABCD ~ EFGH
vredina [299]

Answer:

FG = 20 in

Step-by-step explanation:

∵ ABCD ≈ EFGH

∴ AD/EH = BC/FG

∵ AD = 45 in

∵ EH = 60 in

∴ BC = 15 in

∴ 45/60 = 15/FG

∴ FG = (60 × 15) ÷ 45 = 20 in

4 0
3 years ago
1.5r-3r+8r+2.5r=<br> please show me what the equation is in simplest form thanks
sladkih [1.3K]

Answer:

12.5r

Step-by-step explanation:

You just add all the numbers together and then add the r at the end it’s pretty easy when you know that

7 0
4 years ago
The new iPhone 3.14 is being sold at the UT Math Department. The original price is $1200 (day 0), but they are going to decrease
Marat540 [252]

\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill&50.14\\ P=\textit{initial amount}\dotfill &1200\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=\textit{elapsed time}\dotfill &16\\ \end{cases}


\bf 50.14=1200(1-r)^{16}\implies \cfrac{50.14}{1200}=(1-r)^{16}\implies \sqrt[16]{\cfrac{50.14}{1200}}=1-r \\\\\\ r=1-\sqrt[16]{\cfrac{50.14}{1200}}\implies r\approx 0.18\implies \stackrel{\textit{converting to percent}}{r\approx 0.18\cdot 100}\implies r\approx \stackrel{\%}{18}\quad \leftarrow x

3 0
4 years ago
Which of the g-values satisfy the following inequality?
sleet_krkn [62]

Answer:

B: g=5

C: g=6

Step-by-step explanation:

Given

7 \ge 12 - g

Required

All possible values of g

We have:

7 \ge 12 - g

Collect like terms

7 - 12\ge  - g

-5\ge  - g

Divide both sides by -1 [The inequality changes because of negative division]

5\le  g

Swap both terms

g \ge 5

This implies that g is greater than of equal to 5

i.e.

g= \{5,6,7.....\}

Hence:

(b) and (c) are correct

8 0
3 years ago
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