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Leno4ka [110]
3 years ago
14

Need help ASAP with the correct answer!!!!!!

Mathematics
1 answer:
xenn [34]3 years ago
4 0
All of them except D have no real solutions
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Factor 15x + 35 using the GCF.
stellarik [79]
The answer is A. 5(3x+7)
4 0
2 years ago
PLEASE HELP ASAP!!
Gala2k [10]

Answer:

7.2 feet

Step-by-step explanation:

plug in x = 3 since we are looking for the height after the 3rd bounce

4(0.6)(3)

4(1.8)

7.2

4 0
2 years ago
240,000 written as a whole number multiplied by the power of ten
Stolb23 [73]
This question can be also asked as what is the scientific notation of the number 240,000. The scientific notation is written as <span>a whole number multiplied by the power of ten. It should be written as follows:

2.4 x 10^5

Hope this helps. Have a nice day.</span>
8 0
3 years ago
Solve<br> 4(-5)(-2)(-3)<br> show your work&lt;3<br> no links
laila [671]

Answer:

<h2><em><u>-120</u></em></h2>

Step-by-step explanation:

4(-5)(-2)(-3)

= -20 × 6

= <em><u>-120 (Ans)</u></em>

5 0
2 years ago
Read 2 more answers
Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,
MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

L= 3W_1 ---- initial dimension

W_2 = 6m --- new width

A_2 = 45m^2 --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

Area =Length * Width

A_2=L * W_2

Make L the subject

L = \frac{A_2}{ W_2}

Substitute values for A and W

L = \frac{45m^2}{6m}

L = \frac{45m}{6}

L = 7.5m --- this is the length of the garden

Calculate the initial width:

L= 3W_1

Make W1 the subject

W_1 = \frac{1}{3} * L

W_1 = \frac{1}{3} * 7.5

W_1 = 2.5

So, the initial area is:

A_1 = L_1 * W_1

A_1 = 2.5 * 7.5

A_1 = 18.75

The percentage change in area is:

\%A = \frac{A_2 - A_1}{A_1}

\%A = \frac{45 - 18.75}{18.75}

\%A = \frac{26.25}{18.75}

\%A = 1.4

Express as percentage

\%A = 1.4*100\%

\%A = 140\%

4 0
3 years ago
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