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DiKsa [7]
3 years ago
13

How do you calculate relative velocity?

Physics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

<h3>Vab=Va-Vb</h3><h3>Vab=Vb-Va</h3><h3>Explanation:</h3>

Vab is velocity of a relative to b

Vba is velocity of b relative to a

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A test rocket is launched vertically from ground level (y=0), at time t=0.0s. The rocket engine provides constant upward acceler
Luden [163]

From the definition of average velocity,

\bar v=\dfrac{\Delta y}{\Delta t}=\dfrac{49\,\mathrm m}t,

and the fact that constant acceleration means

\bar v=\dfrac{v_f+v_0}2=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}2=15\,\dfrac{\mathrm m}{\mathrm s}

we can solve for the time t:

15\,\dfrac{\mathrm m}{\mathrm s}=\dfrac{49\,\mathrm m}t\implies t=3.3\,\mathrm s

7 0
3 years ago
When an object is thrown upwards and reaches its maximum height its speed is: a. Greater than the initial
suter [353]

Answer:

Option d

Explanation:

When we throw an object in the upward direction, we provide it with certain initial velocity due to which it covers a certain distance up to the maximum height.

While the object is moving in the upward direction, its velocity keeps on reducing due to the acceleration due to gravity which acts vertically downwards in the opposite direction thus reducing its velocity.

So, the maximum height attained by the object is the point where this upward velocity of the body becomes zero and after that the object starts to fall down.

5 0
3 years ago
Which of the following is a category of mechanical wave?
givi [52]

Answer:

a

because the mechanical wave is when it goes over and over again

8 0
3 years ago
Read 2 more answers
I help much help on 18!!!
ra1l [238]
I think it's something like electrons don't attract, cuz you know the saying "Opposites attract." Cause electrons are negative... Ahaha... sorry, I don't know the answer.
4 0
3 years ago
A 3.0-kg cart is rolling across a frictionless, horizontal track toward a 1.3-kg cart that is held initially at rest. The carts
Karolina [17]

Answer:

Explanation:

a ) Momentum of first cart = mass x velocity

= 3 x 4.6 =+13.8 kg m /s

Momentum of second cart = 1.3 x - 1.9 = - 2.47 kg m /s

Total momentum = 13.8 - 2.47

= +11.33 kg m /s

b )

Let the velocity of first cart be v at the moment when second cart was at rest

total momentum = 3 x v + 0 = 3 v

Applying conservation of momentum law

3 v  = +11.33

v = +3.77 m /s

6 0
3 years ago
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