Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)
I am pretty sure the answer would be a
The distance is 17 and the displacement is 1
Answer:
1.24611
Explanation:
V = Velocity = 10 ft/s
L = Length = 2 ft
g = Acceleration due to gravity = 32.2 ft/s²
Froude number is given by

Converting to SI units




The Froude number is 1.24611
The Froude number is equal. The Froude number is dimensionless as the units cancel each other. In order for this to happen the units used need to be consitent either imperial or SI.
During the fall, all the initial potential energy of the rock

has converted into kinetic energy of motion

where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have

and so we can find the value of K, the kinetic energy of the rock just before hitting the ground: