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sdas [7]
3 years ago
7

which of the following drives the movement of convection currents A. pressure differences B. density differences C. volume diffe

rences 
Physics
2 answers:
AlekseyPX3 years ago
8 0
Convection currents are driven by the buoyancy
that results from density differences.
ozzi3 years ago
5 0
I'd go with B. density differences but don't hold me to that :-)

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When the object is at half its amplitude from equilibrium, is the magnitude of its acceleration at half its maximum value?
Nezavi [6.7K]
We have F = kx or ma = kx where m and k are constants. Therefore, if x is halved, a must be halved too.
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3 years ago
1. Determine the energy released per kilogram of fuel used.
Serga [27]

The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T

Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
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8 0
2 years ago
1.imagine you were able to throw a ball in a frictionless environment such as outer space.once you let go of the ball,what will
Scorpion4ik [409]
Imagine you were able to throw a ball in a frictionless environment
such as outer space.  Once you let go of the ball, it will travel forever
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5 0
3 years ago
A 2 kg ball is thrown upward with a velocity of 15 m/s. What is the kinetic energy of the ball as it is being thrown?
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7 0
3 years ago
Read 2 more answers
A meter stick is free to rotate about an axis through one of its end. Find the force F needed to balance this meter stick if the
Mumz [18]

Answer:

Explanation:

Component of force perpendicular to stick

= F Sin 60°

=√3 / 2 F.

Taking torque about the other end

= √3 / 2 F x 1 Nm

Weight of stick = 60 gm

= 60 x 10⁻³ kg

= 60 x 10⁻³ x 9.8 N

= .588 N

This weight will act from the middle point of stick so torque about the

other end

= .588 x 1 Nm

Balancing these two torques we have

.588 = √3 /2 F

F=\frac{2\times0.588}{\sqrt{3} }

F = 0.679 N

6 0
3 years ago
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