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3 years ago

sarah had 3 cookies in her jar her friend angela took -18 from her jar how many cookies does she have now?

Mathematics

2 answers:

jasenka [17]3 years ago

5 0

If she took -18 then she wouldn’t have taken any I think

s344n2d4d5 [400]3 years ago

3 0

She gonna owned like 20

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Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

3 years ago

Identify the solutions of the inequality 11 ≤ p + 5.

ale4655 [162]

all real numbers greater than or equal to 6

4 0

3 years ago

7x to the power of 2 is a what is it a) monomial b) binomial c) Trinomial

Sedaia [141]

You can use the prefixes to figure this out:
Mono: one
Bi: two
Tri: three

So, because there is only one term, it is a monomial.

4 0

2 years ago

#9. Solve: 8x + 5 = 3x + 15 X = 4 x = 2 x = 20/11 x = 20

Jobisdone [24]

Answer:

x = 2

Step-by-step explanation:

8x + 5 = 3x + 15

8x - 3x + 5 = 3x - 3x + 15

5x + 5 = 15

5x + 5 - 5 = 15 - 5

5x = 10

5x / 5 = 10 / 5

x = 2

6 0

2 years ago

B) What should be subtracted from -7mn + 2m² + 3n² to get m²+ 2mn + n²? please help

Hitman42 [59]

Answer: m²-9mn+2n²

Step-by-step explanation: make use of BODMAS strategy. Let the unknown be x.

-7mn+2m²+3n²-x= m²+2mn+n². Since we are concerned about getting the unknown,let's try to collect the like terms.

-7mn+2m²+3n²-(m²+2mn+n²)= x

-7mn+2m²+3n²-m²-2mn-n²= x

-7mn-2mn+2m²-m²+3n²-n²=x

-9mn+m²+2mn= x

X= m²-9mn+2n²

6 0

3 years ago