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gayaneshka [121]

3 years ago

8

Find the missing measure in the figure. Look to see how the right triangle is being drawn from the picture. Round to the nearest

tenth if necessary.
? ft

1 answer:

igor_vitrenko [27]3 years ago

4 0

That’s a 90 degree angle bro

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Solve for 3/4u = 12<br> .<br> Simplify your answer as much as possible.

Wittaler [7]

Answer:

u = 16

Step-by-step explanation:

Given

$\frac{3}{4}$ u = 12

Multiply both sides by 4 to eliminate the fraction

3u = 48 ( divide both sides by 3 )

u = 16

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What is the value of 3ab+5b-6 when a=1 and b = 3

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The value of 3ab+5b-5 is 18

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A 12 pack of soda cost $3.25 What is the unit price

kakasveta [241]

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Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .

stich3 [128]

$\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}$

$\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}$

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3 years ago

Which table is a proportional relationship?

Tatiana [17]

Answer:

The blue one

4, 2

6, 3

12, 6

Step-by-step explanation:

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3 years ago