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Lapatulllka [165]
3 years ago
13

The precision of a laboratory instrument is ± 0.05 g. The accepted value for your measurement is 7.92 g. Which measurements are

in the accepted range? Check all that apply.
a) 7.85 g
b)7.89 g
c) 7.91 g
d) 7.97 g
e) 7.99 g
Physics
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

b)7.89 g  

c) 7.91 g

d) 7.97 g

Explanation:

The accepted value for the measurement is 7.92 g, while the precision of the instrument is 0.05 g. Therefore, the interval of the accepted values will be the central value plus and minus the precision, so:

- Minimum accepted value: 7.92 g - 0.05 g = 7.87 g

- Maximum accepted value: 7.92 g + 0.05 g = 7.97 g

So, the accepted interval is

7.87 g - 7.97 g

Therefore, all the values that lie within this interval are accepted. So the accepted values are:

b)7.89 g  

c) 7.91 g

d) 7.97 g

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See explanation below

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For water with density of 1000 kg/m³, the mass of the slice

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1000×Δy ×(√(6y-y²))²×π ×g = 1000×Δy ×(√(6y-y²))²×π ×9.81

The work done to move a unit height of y+1 = Force × Distance

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Integrating the entire section of the sphere that is 2×r high, or from 0 to 6 we get

W =\int\limits^6_0 {1000*(6y-y^{2} ) *\pi *9.81 * (y+1)} \, dy

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3 years ago
you slide abox of books at constant speed up a30 degree ramp, applying a force of 200 newtons directed up the slope. The coeffic
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The work done is 400 J

Explanation:

The work done by you in pushing the box along the slope is given by

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Here we have the following:

F = 200 N is the magnitude of the force applied

d=\frac{h}{sin \theta} is the distance covered, where

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Substituting and solving, we find

W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J

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brainly.com/question/6763771

brainly.com/question/6443626

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Answer:

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Given;

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The answer is A ..........
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