Different masses are hung on a spring scale calibrated in newtons. The force exerted by gravity on 1.0 kg is shown in the image
1 answer:
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Kinetic energy, KE, is modeled by the formula 
, where m is the mass in kg and v is the velocity in m/s.
In this scenario, mass and one-half are constant but the velocity changes.
You can see that by squaring twice the velocity, that is equal to four times the original KE. Therefore, the answer is 4k.
In this scenario, mass and one-half are constant but the velocity changes.
You can see that by squaring twice the velocity, that is equal to four times the original KE. Therefore, the answer is 4k.
Answer:
Hits per second=199 hit/s
Explanation:
#Given the angular velocity, , radius of the record
and the distance between any two successive bumps on the groove as
.
The linear speed of the record in meters per second is:
#From above, if the bumps are uniformly separated by 1m, then the rate at which they hit the stylus is:
Hence the bumps hit the stylus at around 199hit/s
Answer:
Explanation:
When the central shaft rotates , the seat along with passenger also rotates . Their rotation requires a centripetal force of mw²R where m is mass of the passenger and w is the angular velocity and R is radius of the circle in which the passenger rotates.
This force is provided by a component of T , the tension in the rope from which the passenger hangs . If θ be the angle the rope makes with horizontal ,
T cos θ will provide the centripetal force . So
Tcosθ = mw²R
Tsinθ component will balance the weight .
Tsinθ = mg
Dividing the two equation
Tanθ =
Hence for a given w , θ depends upon g or weight .