Answer:
she should add solute to the solvent
Explanation:
Given data :
Mass of the sodium chloride, = 20.0 g
Concentration of the solution = 10 g/L
Volume of 20.0 g of sodium chloride = 7.50 mL
Now, from the concentration, we can conclude that for 10 g of sodium chloride volume of the solution is 1 L
thus, for 20 g of sodium chloride volume of the solution is 2 L or 2000 mL
also,
Volume of solution = Volume of solute(sodium chloride) + volume of solvent (water)
thus,
2000 mL = 7.5 mL + volume of solvent (water)
or
volume of water = (2000 - 7.5) mL
or
volume of water = 1992.5 mL
or
volume of water = 199.25 L ≈ 199 L
Answer: Option A : Technician A
Explanation:
The statement/observation, "that the starter motor used to crank diesel engines can draw up to 400 amps of current" made by Technician A is correct.
A diesel engine uses up to 400+ Amperes of electricity to start up a diesel engine in the ignition chamber of motor engine.
Answer:
B.
It will be greater than 10 J.
Explanation:
The total mechanical energy of an object is the sum of its potential energy (PE) and its kinetic energy (KE):
E = PE + KE
According to the law of conservation of energy, when there are no frictional forces on an object, its mechanical energy is conserved.
The potential energy PE is the energy due to the position of the object: the highest the object above the ground, the highest its PE.
The kinetic energy KE is the energy due to the motion of the object: the highest its speed, the largest its KE.
Here at the beginning, when it is at the top of the roof, the baseball has:
PE = 120 J
KE = 10 J
So the total energy is
E = 120 + 10 = 130 J
As the ball falls down, its potential energy decreases, since its height decreases; as a result, since the total energy must remain constant, its kinetic energy increases (as its speed increases).
Therefore, when the ball reaches the ground, its kinetic energy must be greater than 10 J.
Answer:
Explanation:
a) Force of friction = μ R where μ is coefficient of kinetic friction and R is reaction force
R = mg where m is mass of the block
Force of friction F = μ x mg
= .173 x 12.2 x 9.8
= 20.68 N
b ) Only force of friction is acting on the body so
deceleration = force / mass = 20.68 / 12.2 = 1.7 m /s²
acceleration = - 1.7 m /s²
c )
v² = u² - 2 a s
v = 0 , u = 3.9 m /s
a = 1.7 m /s
0 = 3.9² - 2 x 1.7 x s
s = 4.47 m
