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3 years ago

Which statement best describes inertia?

Physics

2 answers:

alukav5142 [94]3 years ago

4 0

B if earth had no atmosphere a baseball would fall towards earth at a faster rate

sattari [20]3 years ago

4 0

D is the answer

Correct me if im wrong

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What is the empirical formula of a compound that contains 27.0% s

eduard

Answer:

Empirical formula of the compound = SOCl₂

Explanation:

QUESTION:What is the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass?

The empirical formula of a compound is its simplest formula. It tells us

* The component element present in a molecule of the compound.

* The ratio in which these elements are combined together, i.e mole ratio.

To calculate the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass. ( Relative atomic mass of S=32gmol⁻¹, 0=16gmol⁻¹, Cl=35.5gmol⁻¹)

Sulphure S, Oxygen O, Chlorine Cl

percentage by mass: 27.0% 13.4% 59.6%

Step 1:

Divide by their relative

atomic mass: 27.0/32.0 13.4/16.0 59.6/35.5

⇒⇒⇒⇒⇒⇒⇒⇒⇒ 0.844 0.838 1.679

Step 2:

Divide by the

smallest mole ratio: 0.844/0.838 0.838/0.838 1.679/0.838

∴ 1 : 1 : 2.

from the analysis above, the compound contains Sulphur, Oxygen and Chlorine in the ratio of 1:1:2.

∴ Empirical formula of the compound = SOCl₂

6 0

3 years ago

TRICARE is health insurance for what part of the population?

Otrada [13]

Answer:

TRICARE for Life (TFL), a program for Medicare-eligible military retirees and their dependents, acts as a supplement to Medicare.

Explanation:

8 0

3 years ago

which of the following described qualitative data? a. recording the temperature of a solid as it is warmed. b. noting the color

UNO [17]

Noting cloudiness occurs when two solutions are mixed.

8 0

3 years ago

Read 2 more answers

A satellite has a mass of 5832 kg and is in a circular orbit 4.13 × 105 m above the surface of a planet. The period of the orbit

elena55 [62]

Answer:

W = 28226.88 N

Explanation:

Given,

Mass of the satellite, m = 5832 Kg

Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m

The time period of the orbit, T = 1.9 h

= 6840 s

The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

$T = 2\pi \sqrt{\frac{(R+h)^{3} }{R^{2} g} }$ second

Squaring the terms and solving it for 'g'

g = 4 π² $\frac{(R+h)^{3} }{R^{2}T^{2} }$ m/s²

Substituting the values in the above equation

g = 4 π² $\frac{(4.38X10^6+4.13X10^5)^{3} }{(4.38X10^6)^{2}X6840^{2}}$

g = 4.84 m/s²

Therefore, the weight

w = m x g newton

= 5832 Kg x 4.84 m/s²

= 28226.88 N

Hence, the weight of the satellite at the surface, W = 28226.88 N

8 0

3 years ago

What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?

Alex Ar [27]

Answer:

750 J

Explanation:

lets convert mass into kg first , 150 /1000 = 0.15 kg

kinetic energy = $\frac{mv^{2} }{2}$ = $\frac{0.15*100^{2} }{2} = 750 J$

3 0

3 years ago