To solve this problem we will apply the relation of Ohm's law, at the same time we will use the concept of resistance in a cable, resistivity and potential difference.
According to Ohm's law we have to
![V= IR](https://tex.z-dn.net/?f=V%3D%20IR)
Here,
V = Voltage
I = Current
R = Resistance
At the same time resistance can be described as
![R = \frac{\rho l}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B%5Crho%20l%7D%7BA%7D)
Here,
= Resistivity of the material
l = Length of the specimen
A = Cross-sectional area
From the above expression we can write the current as,
![I = \frac{V}{R}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7BR%7D)
![I = \frac{V}{\frac{\rho l}{A}}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7B%5Cfrac%7B%5Crho%20l%7D%7BA%7D%7D)
![I =\frac{VA}{\rho l}](https://tex.z-dn.net/?f=I%20%3D%5Cfrac%7BVA%7D%7B%5Crho%20l%7D)
Replacing we have that,
![I = \frac{(0.8V)(0.4*10^{-6}m^2)}{(5.6*10^{-8}\Omega \cdot m)(1.5m)}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B%280.8V%29%280.4%2A10%5E%7B-6%7Dm%5E2%29%7D%7B%285.6%2A10%5E%7B-8%7D%5COmega%20%5Ccdot%20m%29%281.5m%29%7D)
![I = 3.809A](https://tex.z-dn.net/?f=I%20%3D%203.809A)
Therefore the current in the wire is 3.809A
<em>Note: The value obtained for the resistivity of Tungsten was theoretically obtained and can be consulted online.</em>
Answer:
naturally occurring
Explanation:
it has to come from the earth and not be man made
Answer:
The current in the rods is 171.26 A.
Explanation:
Given that,
Length of rod = 0.85 m
Mass of rod = 0.073 kg
Distance ![d = 8.2\times10^{-3}\ m](https://tex.z-dn.net/?f=d%20%3D%208.2%5Ctimes10%5E%7B-3%7D%5C%20m)
The rods carry the same current in the same direction.
We need to calculate the current
I is the current through each of the wires then the force per unit length on each of them is
Using formula of force
![\dfrac{F}{L}=\dfrac{\mu_{0}I^2}{2\pi d}](https://tex.z-dn.net/?f=%5Cdfrac%7BF%7D%7BL%7D%3D%5Cdfrac%7B%5Cmu_%7B0%7DI%5E2%7D%7B2%5Cpi%20d%7D)
![\dfrac{mg}{L}=\dfrac{\mu_{0}I^2}{2\pi d}](https://tex.z-dn.net/?f=%5Cdfrac%7Bmg%7D%7BL%7D%3D%5Cdfrac%7B%5Cmu_%7B0%7DI%5E2%7D%7B2%5Cpi%20d%7D)
Where, m = mass of rod
l = length of rod
Put the value into the formula
![I^2=\dfrac{mgd}{\mu L}](https://tex.z-dn.net/?f=I%5E2%3D%5Cdfrac%7Bmgd%7D%7B%5Cmu%20L%7D)
![I^2=\dfrac{0.073\times9.8\times8.2\times10^{-3}}{2\times10^{-7}}](https://tex.z-dn.net/?f=I%5E2%3D%5Cdfrac%7B0.073%5Ctimes9.8%5Ctimes8.2%5Ctimes10%5E%7B-3%7D%7D%7B2%5Ctimes10%5E%7B-7%7D%7D)
![I=\sqrt{29331.4}](https://tex.z-dn.net/?f=I%3D%5Csqrt%7B29331.4%7D)
![I=171.26\ A](https://tex.z-dn.net/?f=I%3D171.26%5C%20A)
Hence, The current in the rods is 171.26 A.
Answer:
37.5 J
Explanation:
With work done equation: W=Fs
W=75*0.50=37.5 J
or use mgh=(75)(0.5) which is the same
Imagine a crowd of people al jumping around in a room blindfolded. they will bump into each other and the walls. molecules behave the same way as a result of their temperature. the hotter the temperature, the more jumping and the greater the 'pressure' on the walls.