Do Small objects exert no gravitational force ? True or false

Physics

1 answer:

Zanzabum3 years ago

6 0

Answer:

False -

F = G M1 M2 / R^2

So F depends on M1 and M2 and as long either is not zero there will be a gravitational force between them.

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Two sacks contain the same number of identical apples and are separated by a distance r. The two

andrezito [222]

Answer:

The appropriate response will be " $F_2=\frac{3}{4}F$ ". A further explanation is given below.

Explanation:

According to the question,

⇒ $F_1=\frac{G(m_1 m_2)}{r^2}$ ....(equation 1)

and,

⇒ $F_2=\frac{G(m_1 m_2)}{r^2}$ ....(equation 2)

Now,

On dividing both the equations, we get

⇒ $\frac{F_1}{F_2}=\frac{\frac{G(2)(2)}{(1)^2}}{\frac{G(1)(3)}{(1)^2}}$

⇒ $\frac{F_1}{F_2}= \frac{4}{3}$

⇒ $F_2=\frac{3}{4}F$

4 0

3 years ago

Most of an atom is empty space.<br> a. True<br> b. False

Iteru [2.4K]

<span>Yes, the vast majority of an atom is indeed empty space. Most of it's mass is centered in the nucleus. Flying around the nucleus are the electrons, but they're very very far away (on an atomic level anyway). Most of the atom is the space between the nucleus and the electrons.</span>

6 0

3 years ago

Read 2 more answers

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.