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agasfer [191]
3 years ago
8

A machine that is used to print newspaper is a

Physics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

4

Explanation:

They are basically offset web presses constructed using high grade steel and cast iron.

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HELPPPP!!!!
Dafna1 [17]

Answer:

Carbon: 1

Oxygen: 2

Explanation:

Carbon dioxide, or CO₂, has 1 carbon atom and 2 oxygen atoms per mole.

7 0
4 years ago
Read 2 more answers
A right triangle has sides measuring 5 and 12 inches. If the two vectors have a magnitude of 5 and 12 and are at right angles to
ollegr [7]

Answer:

x=13

Explanation:

From the question we are told that

Magnitude 1 M_1=5

Magnitude 1 M_2=12

Generally the Pythagoras equation for the magnitudes is mathematically given as

\sqrt{x^2}=\sqrt{M_1^2 +M_2^2}

\sqrt{x^2}=\sqrt{5^2 +12^2}

x=13

Therefore resultant magnitude is

x=13

8 0
3 years ago
A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
Lilit [14]

Answer:

v = 1.08 m/s

Explanation:

What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?

The decrease in PE is

d = 80.0cm * 1 / 1000m = 0.80m

h = 0.80 m /2 = 0.40 m

ΔPE = m*g*h

ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m

ΔPE = 0.1176 J

The moment of inertia of the assembly is

I = 1/12*m*L² + (m1 + m2)*(L/2)²

I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²

I = 0.032 kg·m²

KE = ½Iω²

0.1176 J = ½ * 0.032kg·m² * ω²

ω = 2.71 rad/s

v = ωr = 2.71 rad/s * 0.400m

The linear velocity

v = 1.08 m/s

3 0
3 years ago
A 20 g ball of clay traveling east at 3.5 m/s collides with a 35 g ball of clay traveling north at 2.0 m/s .
Elanso [62]

The movement direction of the resulting 55 g blob of clay 45o north of east  and the speed of the resulting 55 g blob of clay is 1.8 m/s.

Calculation:-

Let us consider the east direction as the positive X-direction and the north direction as the positive Y-direction.

Mass of the first ball of clay = m1 = 20 g = 0.02 kg

Mass of the second ball of clay = m2 = 35 g = 0.035 kg

Initial velocity of the first ball of clay = V1 = 3.5 m/s  to the east

Initial velocity of the second ball of clay = V2 = 2 m/s  to the north

Final velocity of the blob of clay = V3

X-component of the final velocity of the blob of clay = V3x

Y-component of the final velocity of the blob of clay = V3y

By conservation of linear momentum in the X-direction,

m1V1 = (m1 + m2)V3x

(0.02)(3.5) = (0.02 + 0.035)V3x

V3x = 1.273 m/s

By conservation of linear momentum in the Y-direction,

m2V2 = (m1 + m2)V3y

(0.035)(2) = (0.02 + 0.035)V3y

V3y = 1.273 m/s

V3 = 1.8 m/s

A) Movement direction of the resulting 55 g blob of clay = 45o north of east

B) Speed of the resulting 55 g blob of clay = 1.8 m/s

Mass, in physics, quantitative measure of inertia, a essential property of all count. it's miles, in effect, the resistance that a body of rely gives to a alternate in its pace or function upon the software of a pressure. The more the mass of a body, the smaller the alternate produced with the aid of an implemented pressure.

Learn more collision here:-

brainly.com/question/4403635

#SPJ4

5 0
2 years ago
If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"

Mathematically,

\frac{T^2}{a^3}=const.

Where

T is the orbital period

a is the semi-major axis of the orbit

In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, a: but as we saw from the previous equation, the orbital period of the Earth is proportional to a, therefore as a increases, T increases as well.

Therefore, the period of the orbit would increase.

Learn more about Kepler's third law:

brainly.com/question/11168300

#LearnwithBrainly

5 0
4 years ago
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