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3 years ago

What is a conservative force?

Physics

1 answer:

almond37 [142]3 years ago

8 0

Answer:

A conservative force is a force with the property that the total work done in moving a particle between two points is independent of the path taken Equivalently if a particle travels in a closed loop the total work done by a conservative force is zero

Explanation:

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A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.

podryga [215]

Answer:

Hi, There! my name is Jay And I'm here to help!

<h2>Question</h2>

A ____ is a region where jets of gas from young stars impact and heat the gas surrounding the young star.

<h2>Answer</h2>

bipolar outflow

Explanation:

A bipolar outflow is a stream of matter in two opposing directions from a object, Most likely a star.

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Hope this Helps!

Take Care!

Have a great day!

$-Jay-$

3 0

3 years ago

Read 2 more answers

To make a bounce pass, a player throws a 0.60-kg basketball toward the floor. The ball hits the floor with a speed of 5.4 m/s at

artcher [175]

Answer:

2.74 N-s

Explanation:

m = mass of the basketball thrown towards the floor = 0.60 kg

v₀ = initial speed of the ball before hitting the floor = 5.4 m/s

θ = angle made by the direction of motion of the ball with the vertical before and after the collision = 65°

I = Impulse delivered to it by the floor

Impulse delivered to the ball by the floor is given as

I = 2 m v₀ Cosθ

Inserting the values

I = 2 (0.60) (5.4) Cos65

I = 2.74 N-s

5 0

4 years ago

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Tatiana [17]

Explanation:

Given that,

Mass of ball, m = 0.425 kg

Initial speed of the ball, u = 12 m/s

Initial speed of a person, u' = 0

Mass of a person, m' = 68 kg

(a) Let V is the combined speed of the person and the ball. Using conservation of momentum as :

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{0.425\times 12+0}{(0.425+68)}\\\\V=0.0745\ m/s$

(b) If the ball hits the person and bounces off his chest, so afterwards it is moving horizontally at 9.00 m/s in the opposite direction,. Let v' is the speed of the person after the collision. So,

$mu+m'u'=mv+m'v'$

v = -9 m/s

$mu=mv+m'v'\\\\v'=\dfrac{m(u-v)}{m'}\\\\v'=\dfrac{0.427\times (12-(-9))}{68}\\\\v'=0.131\ m/s$

Hence, this is the required solution.

4 0

3 years ago

Give an example of how the relationship between force and acceleration might affect YOU.

IrinaK [193]

Take a car collision as an example, the more you speed up as means of acceleration, the more force will be on impact.

5 0

3 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$