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ZanzabumX [31]
3 years ago
15

A right triangle has sides measuring 5 and 12 inches. If the two vectors have a magnitude of 5 and 12 and are at right angles to

each other, then what is their resultant? Use the Pythagorean theorem to calculate the resultant.
Physics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

x=13

Explanation:

From the question we are told that

Magnitude 1 M_1=5

Magnitude 1 M_2=12

Generally the Pythagoras equation for the magnitudes is mathematically given as

\sqrt{x^2}=\sqrt{M_1^2 +M_2^2}

\sqrt{x^2}=\sqrt{5^2 +12^2}

x=13

Therefore resultant magnitude is

x=13

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A rocket is launched from a height of 3 m with an initial velocity of 15 m/s What is the maximum height of the rocket? When will
Fudgin [204]

If no extra acceleration is added to the rocket, then its velocity at time <em>t</em> is

<em>v</em> = 15 m/s - <em>g t</em>

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Also, recall that

<em>v</em>² - <em>u</em>² = 2 <em>a </em>∆<em>x</em>

where <em>u</em> is initial speed, <em>v</em> is final speed, <em>a</em> is acceleration, and ∆<em>x</em> is net displacement.

At the rocket's maximum height ∆<em>x</em>, the velocity is 0. So, the maximum height is

0² - (15 m/s)² = 2 (-<em>g</em>) ∆<em>x</em>

∆<em>x</em> = (15 m/s)² / (2 * (9.80 m/s²)) ≈ 11.48 m

But this assumes the rocket is launched from the ground. We're given that the rocket is launced from 3 m above the ground, so we need to add this to the height above. So the maximum height is closer to 14.48 m.

As mentioned before, this happens when vertical velocity is 0:

0 = 15 m/s - <em>g t</em>

<em>t</em> = (15 m/s) / (9.80 m/s²) ≈ 1.53 s

5 0
3 years ago
A 1369.4 kg car is traveling at 28.9 m/s when the driver takes his foot off the gas pedal. It takes 5.1 s for the car to slow do
Darya [45]

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

7 0
3 years ago
A wave has a frequency of 35 Hz and a wavelength of 15 meters,<br> what is the speed of the wave?
Mila [183]

Answer:

f lamda = c

Explanation:

525 m/s is the speed

5 0
2 years ago
Explain how the earth is round and not flat
frosja888 [35]
It is a conglomeration of rock that collected together over time, and it rotating in a spinning ball that is orbiting a sun that is in the middle of our solar system. 

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5 0
3 years ago
Read 2 more answers
Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carryin
Vedmedyk [2.9K]

Answer:

The correct answer is 2.8*10^{-5}ms^{-1}

Explanation:

The formula for the electron drift speed is given as follows,

u=I/nAq

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is 8.93/63.5 molcm^{-3}. Converting this number to m³ using very elementary unit conversion we get 140384molm^{-3}. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}

if we convert the area from mm³ to m³ we get A=80*10^{-6}m^{2}.So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,

u=30/(8.45*10^{28}*80*10^{-6}*1.602*10^{-19})\\u=2.8*10^{-5}m.s^{-1}

which is our final answer.

6 0
3 years ago
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