Answer:
only neon has electron i n it's outer shell.so it reacts normally.other given elements do not have 8 electron in its outer shell.
The potential difference across a 1500 ohm resistor carrying a current of 0.075 A is approx. equal to 113 V.
Explanation:
An ideal electrical circuit obeys Ohm's law. As per this law, the potential difference in any electrical circuit will be directly proportional to the current flowing in that circuit. And the proportionality constant is the resistance offered by the circuit.
![V = I * R](https://tex.z-dn.net/?f=V%20%3D%20I%20%2A%20R)
As here, the current is said to be carried as 0.075 A and the resistance is 1500 ohm, then the potential difference will be
![V = 0.075 * 1500 =112.5 = 113 V](https://tex.z-dn.net/?f=V%20%3D%200.075%20%2A%201500%20%3D112.5%20%3D%20113%20V)
Thus, the potential difference across a 1500 ohm resistor carrying a current of 0.075 A is approx. equal to 113 V.
Answer:
Radiation
Explanation:
The heat transfer take place by three modes
1. Conduction
This type of heat transfer take place in the solid materials like metals .This heat transfer take place due to vibration of electron.
2.Convection
This type of heat transfer take place in the moving fluid like water ,air etc.
3.Radiation
Every materials which having temperature above 0 K are emitting radiation.This type of heat transfer dominate at the high temperature.
We know that temperature of sun is so high so the heat transfer from sun to the earth is take place by radiation mainly.
Answer:
232.9m³ (Option b. is the closest answer)
Explanation:
Given:
Air pressure in the lab before the storm, P₁ = 1.1atm
Air volume in the lab before the storm, V₁ = 180m³
Air pressure in the lab during the storm P₂ = 0.85atm
Air volume in the lab before the storm, V₂ = ?
Applying Boyle's law: P₁V₁ = P₂V₂ (at constant temperature)
![V_{2} = \frac{P_{1}V_{1}}{P_{2}}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BP_%7B2%7D%7D)
![V_{2} = \frac{1.1 * 180}{0.85}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%5Cfrac%7B1.1%20%2A%20180%7D%7B0.85%7D)
![V_{2} = \frac{198}{0.85}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%5Cfrac%7B198%7D%7B0.85%7D)
V₂ = 232.9m³
The air volume in the laboratory that would expand in order to make up for the large pressure difference outside is 232.9m³
Answer:
The SI unit of power is the watt
Explanation: