If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
1 answer:
The period of the orbit would increase as well
Explanation:
We can answer this question by applying Kepler's third law, which states that:
"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"
Mathematically,
Where
T is the orbital period
a is the semi-major axis of the orbit
In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, : but as we saw from the previous equation, the orbital period of the Earth is proportional to
, therefore as
increases, T increases as well.
Therefore, the period of the orbit would increase.
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Answer:
Displacement from the starting position is 103.21m
Explanation:
If you draw these directions, it will create the two legs of a triangle.
Using this method, you can visualize why your displacement is what it is.
Using the pythagorean theorem
Plug in both values
c = 103.2085
c= 103.21
The Electric field is zero at a distance 2.492 cm from the origin.
Let A be point where the charge C is placed which is the origin.
Let B be the point where the charge C is placed. Given that B is at a distance 1 cm from the origin.
Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.
i.e., at distance 'x' from B.
Using Coulomb's law, ,
=
k is the Coulomb's law constant.
On substituting the values into the above equation, we get,
Taking square roots on both sides and simplifying and solving for x, we get,
1.67x = 1+x
Therefore, x = 1.492 cm
Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.
Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926
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