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During the collision between two balls on the pool table there is no external force along the line of collision between them
Since there is no external force on it so here we can say
here we have
so we can say
since there is no external force so we can say during the collision the momentum of two balls will remain conserved
Answer:
= ( ρ_fluid g A) y
Explanation:
This exercise can be solved in two parts, the first finding the equilibrium force and the second finding the oscillating force
for the first part, let's write Newton's equilibrium equation
B₀ - W = 0
B₀ = W
ρ_fluid g V_fluid = W
the volume of the fluid is the area of the cube times the height it is submerged
V_fluid = A y
For the second part, the body introduces a quantity and below this equilibrium point, the equation is
B - W = m a
ρ_fluid g A (y₀ + y) - W = m a
ρ_fluid g A y + (ρ_fluid g A y₀ -W) = m a
ρ_fluid g A y + (B₀-W) = ma
the part in parentheses is zero since it is the force when it is in equilibrium
ρ_fluid g A y = m a
this equation the net force is
= ( ρ_fluid g A) y
we can see that this force varies linearly the distance and measured from the equilibrium position
Explanation:
The given data is as follows.
Resistance (R) = 1200 ohm, Area (A) = m (as
)
Diameter (d) = 2.3 mm = m
First, we will calculate the length as follows.
R =
Here, = resistivity of aluminium =
Putting the given values above and we will calculate the value of length as follows.
R =
1200 =
L =
As the circumference of circular wire =
or, =
=
And, number of turns will be calculated as follows.
No. of turns × Circumference = Length of wire
No. of turns ×
=
Thus, we can conclude that turns of wire are needed.