1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1
Chromium is strange because it moves on to the 4s orbital instead of filling the 3d orbital with that last electron. Tricky.
Mark as brainliest if this helped! :)
V₁ = initial Volume of the balloon after it is blown up = 365 L
V₂ = new Volume of the balloon after it is taken outside = ?
T₁ = initial temperature of the balloon = 283 K
T₂ = new temperature of the balloon = 300 K
using the equation
V₁/V₂ = T₁/T₂
365/V₂ = 283/300
V₂ = 387 L
Answer : The value of rate of reaction is 
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The given chemical equation is:

Rate law expression for the reaction is:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
As per question,
a = order with respect to
= 2
b = order with respect to
= 1
Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of rate of reaction by using the rate law expression.
Given :
k = rate constant = 
[NO] = concentration of NO = 
= concentration of
= 
Now put all the given values in the above expression, we get:


Hence, the value of rate of reaction is 