If the water vapor content stays the same and the temperature drops, the relative humidity increases. If the water vapor content stays the same and the temperature rises, the relative humidity decreases. This is because colder air doesn't require as much moisture to become saturated as warmer air.
Answer:200ML
Explanation:from quiz ck-12
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
The answer is actually Ionization Energy. I just took the quiz.
In order to calculate the new freezing point, we must first find the depression. This is given by:
ΔT = Kf * b * i
where Kf is the cryscopic constant for the solvent, b is the molarity of the solution in moles per kilogram and i is the van't Hoff factor, which tells us how many ions will be released when a substance is dissolved.
Kf = 1.853, b = 1.5, i = 2 (Na⁺ and Cl⁻)
ΔT = 5.5 °C
The new freezing point will be 0 + 5.5
5.5 °C
