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ELEN [110]
2 years ago
15

Find the product of the binomials, (x - 3)(x + 2) (x + 4) =

Mathematics
2 answers:
MrRa [10]2 years ago
7 0

Answer:

x^3+3x^2-10x-24

Step-by-step explanation:

(x - 3)(x + 2) (x + 4)

multiply the first two together first

(x^2+2x-3x-6)(x+4) add like terms first

(x^2-x-6)(x+4)

then multiply

x^3+4x^2-x^2-4x-6x-24

add like terms

x^3+3x^2-10x-24

erastovalidia [21]2 years ago
6 0

Answer:

Step-by-step explanation:

(x - 3)(x + 2) (x + 4) =

x^3+3x^2-10x-24

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∠C and ​ ∠D ​ are vertical angles with m∠C=−3x+58 and m∠D=x−2 .<br><br><br><br> What is m∠D ?
11111nata11111 [884]
Vertical angles are equal

-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15

m < D = x - 2....15 - 2 = 13 <====
m < C = -3x + 58....-3(15) + 58 = 13 
4 0
3 years ago
Read 2 more answers
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Firlakuza [10]

Answer:

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Step-by-step explanation:

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4 0
1 year ago
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This is the last time its happened twice please i need the answer
slamgirl [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Can someone please help me?
koban [17]

Answer:

The X intercepts= 1 and -1

The y= -1

Step-by-step explanation:

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7 0
3 years ago
I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th
stellarik [79]

Answer:

The number of once is 9.1  

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18             .........1

100 × H + 1 × O = 900          ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴   H = \frac{882}{99}

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e  O = 18 - 8.9

∴    O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1  and The number of hundreds is 8.9

Answer

4 0
3 years ago
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