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malfutka [58]
3 years ago
7

The probability distribution table shows the proportion of people living in the five different regions of a city there are now 4

200 residents in the city.
How many live in the south region?

Photo attached

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer: Number of residents live in south region= 672 residents.


Step-by-step explanation:

Given:- Total residents in the city =4200

let A be the event of residents live in south region the,

Probability of residents live in south region P(A) = 0.16

So, Number of residents live in south region=Product of probability of residents live in south region and total residents in the city =0.16×4200=672 residents.

const2013 [10]3 years ago
4 0
Since there are a total of 4,200 residents and the question is asking for the amount in the south region, take the distribution number from the chart, 0.16, and multiply it by 4,200.
4200 ×.16 = 672

672 residents
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4: The divisors are 4, 2 and 1

5: The divisors are 5 and 1

6: The divisors are 6, 3 and 1

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So, the number of ways in which we can create a factorfic number is determined by the following cases:

  • The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    2          </u>=   8

number 1    number 2    number 3   number 4  number 5  number 6

At the same way we can calculate the following cases:

  • The number 2 is blue and the number 3 is red:  If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    1          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is red:  If the number 2 and 3  are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>           1   </u>  *<u>         2    </u>* <u>    1          </u>=  2

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is blue:  If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          1   </u>  *<u>         2    </u>* <u>    2          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

P= \frac{18}{64} =  0.28125

4 0
3 years ago
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