Answer:

Step-by-step explanation:
Given :
Two points are given in graph (-6, -4) and {7, 5).
The point-slope form of the equation of a straight line is:
------------(1)
Let
and 
The slope of the line 
Put all known value in above equation.



The slope of the line 
We know m, and also know that
, so we put these value in equation 1.

Therefore, the equation of the line is
.
Answer:
Mean = 90, Median = 93, Mode = 90, Range = 6
Step-by-step explanation:
Mean:
96 + 90 + 94 + 93 + 90 = 463
463 ÷ 5 = 92.5
92.5 to nearest tenth = 90
Mean = 90
Median:
<em>90, 90</em>, <u>93</u>, <em>94 ,96</em>
Median = 93
Mode
<em>96, </em><u>90</u><em>, 94, 93, </em><u>90</u><em> </em>
Mode = 90
Range:
96 - 90 = 6
Range = 6
I think its 1.25ft but i could be wrong... sorry if im wrong
Answer:
18 in
Step-by-step explanation:
Okay so first subtract 9x^2-10x+1 which gives you (9x -1)(x-1). then do the same to the next one which gives you -2(x^2 -2x +5) when you subtract you should get 11x^2 - 14x +11