A table would help to organize more information than a graph would. A graph would help more with numbers.
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer:
it approx 103.2 degree
Step-by-step explanation:
s=90+tan^-1(1÷3√2)
I add 90 base on the coordinate , taking the centre of the circle place at origin
Answer:
x = -2 or x = 1/3 thus: B & C
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 + 7 x - 2 = 2 x - x^2
Subtract 2 x - x^2 from both sides:
3 x^2 + 5 x - 2 = 0
The left hand side factors into a product with two terms:
(x + 2) (3 x - 1) = 0
Split into two equations:
x + 2 = 0 or 3 x - 1 = 0
Subtract 2 from both sides:
x = -2 or 3 x - 1 = 0
Add 1 to both sides:
x = -2 or 3 x = 1
Divide both sides by 3:
Answer: x = -2 or x = 1/3
The last one is correct answer
