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Arte-miy333 [17]
3 years ago
9

Pauley graphs the change in temperature of a glass of hot tea over time. He sees that the function appears to decrease quickly a

t first, then decrease more slowly as time passes.What best describes thiz ?
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer: We know that an "exponential growth" is that where a function start growing slowly and after start increasing more quickly.

a "logarithmic growth" is the opposite of this, at first you will see a quick increase, that after some time gets slower.

But in this case we are searching for decays: The decays are the opposite of the growths, an "logarithmic decay" starts slow and gets faster latter, and an "exponential decay" decreases very quickly at first, and latter more slowly.

Then, the model for the temperature of the hot tea over the time is a "exponential decay", this is a function of the form T(x) = T₀e^{-kt}, where T₀ is the initial temperature, t is the time, and k is a constant number.

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Find the midpoint of points A(-6, -5) and B(4,3) graphically.
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Answer:

(-1,-1)

Step-by-step explanation:

4-6         3-5

-------   ,   ---------

 2               2

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Plz write this on paper help me and send it❤️
vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

4. 40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325

5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}

7 0
3 years ago
What is the equation of the line that passes through the point (-1, -7) and has a<br> slope of 2?
o-na [289]

Answer:

(a,b)------>(-1,-7)let

now

m(x-a)=(y-b)

2(x+1)=(y+7)(where m=slope

2x+2=y+7

2x-y=7-2

2x-y=5 is a required equation.

7 0
3 years ago
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