Answer:
(-14,-4)
Step-by-step explanation:
Given the pre-image A=(-7,-2)
If A is dilated with a scale factor of 2
Then the image of A,
A' = (-7,-2) X 2
We multiply each coordinate point by 2
=(-7*2,-2*2)=(-14,-4)
Therefore, the point A' would be: (-14,-4)
2x +4y =10x-3y =12
2x +4y =12 -----eq. 1
10x-3y =12 -------eq.2
2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y
Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23
Now, substitute this value of y in any equations given above
10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
Answer:
W'(8,5) X'(7,-5) Y'(-8,10) Z'(-4,-10)
I would say that this is the answer, but when I graphed it out, it didn't make a rectangle, so I believe that you or your teacher typed something wrong.
19.4 divided by 2, to find the radius. Then square it, and then multiply it by pi. Which gives you A as the answer
