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Llana [10]
3 years ago
13

50+ points. Trapezoid EFGH has been rotated 180 degrees around the origin and then reflected across the y‐axis. Which of the fol

lowing transformations would return the trapezoid to its original position? Reflection across the line y=x Reflection across the x‐axis Reflection across the y‐axis Rotation of 180 degrees around the origin
Mathematics
2 answers:
shepuryov [24]3 years ago
7 0
Reflection across the x-axis
Tatiana [17]3 years ago
7 0

Answer:

reflection across the x-axis is correct i got it right

Step-by-step explanation:


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What is the area of a square with a side length of 7 feet ? <br><br> HELP
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49 square feet

Step-by-step explanation:

Area of square

=  {7}^{2}  \\  \\  = 49 \:  {ft}^{2}  \\

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What is the second transformation
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A rotation about point H
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he gave him 4 books.

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5 0
3 years ago
Jack travels to work on the Eastern Freeway. He notices that the difference in time between if he drives 5 mph below the speed l
Misha Larkins [42]
Let's denote s as the speed limit. To find the total time it takes for Jack to drive given the speed, we just divide the total number of miles he covered (10 miles) by the speed he's traveling at.

Accounting for the given of the problem, we'll have the following equation:
\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30} (from the fact that the difference between the time it takes to drive five miles below the speed limit versus 15 miles below is 2 mins or \frac{1}{30} hours.)

Since we only have one unknown variable, we can freely solve for s:
\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30} 
\frac{10(s-5)-10(s-15)}{(s-15)(s-5)}= \frac{1}{30} 
\frac{10s-50-10s+150}{s^{2}-5s-15s+75}= \frac{1}{30} 
\frac{100}{s^{2}-20s+75}= \frac{1}{30}  
3000=s^{2}-20s+75
0=s^{2}-20s-2925
s_{1}=65
s_{2}=-45 (we ignore the negative value since there is no negative <u>speed</u>.)

ANSWER: The speed limit of the freeway is 65 mph.
3 0
4 years ago
Read 2 more answers
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