Answer: Tristan can pick them out in 6 different ways
Step-by-step explanation: In the waiting room the four magazines all have an equal chance of being picked first and then others would be picked subsequently. If we are to pick magazine A first of all, then the others would be picked as B, C and D, or C, B and D, or D, B and C, and so on.
However, rather than spend so much time counting the different ways we can apply the mathematical method of permutation. Since choosing the first one means we can’t choose it again but others have to be chosen, and all four magazines each has an equal chance of being chosen first, then the number of all possible permutations is given as 4! (four factorial).
The question requires us to chose three out of the four magazines, so we shall apply 3!.
3! = 3 x 2 x 1
3! = 6
Therefore, there are 6 different ways to pick three out of the four magazines
Answer:
the answer should be 4.71828182846
Hi there!
The way that an infinite number of solutions is achieved is when the two equations, when solved together, get an answer which is just a number equal to the same number. To do this, first substitute 6x-b in for y in the second equation.
Now, we see that b needs to be equal to -3 when multiplied by -1/2. When both sides are divided by -1/2, b becomes equal to 6. Thus, b must be 6.
Check work:
Thus, as they are equal to each other, the answer is correct. b = 6.
Hope this helps!
{(sin (x))^2A(csc(x))^3(cos))3B+(-3x)
{cot (dx) cos (x)
Answer:
A is the correct answer
Step-by-step explanation:
