0.0793 kg= __ cg please help fast.

Mathematics

2 answers:

Inga [223]4 years ago

7 0

0.0793 kg equals 7930 cg

Olegator [25]4 years ago

6 0

The answer is 7930 cg.

You might be interested in

Perform the indicated operation

dimulka [17.4K]

The Answer is D!!
Hope this helps

4 0

2 years ago

What is sin θ when sec θ = square root of 5? Rationalize the denominator if necessary.

alexandr1967 [171]

$\bf sec(\theta )=\sqrt{5}\implies \cfrac{1}{cos(\theta )}=\sqrt{5}\implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{5}}}=cos(\theta )~\hfill \leftarrow \stackrel{\textit{let's find the}}{\textit{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{(\sqrt{5})^2-1^2}=b\implies \pm\sqrt{5-1}=b\implies \pm\sqrt{4}=b\implies \pm 2=b \\\\[-0.35em] ~\dotfill\\\\ sin(\theta )=\pm\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{\sqrt{5}}}\implies \stackrel{\textit{rationalizing the denominator}}{\pm\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \pm\cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \pm\cfrac{2\sqrt{5}}{5}}$