Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Answer:
46/100
Step-by-step explanation:
also what grade is this
Answer:
x^2 / 25 + y^2 / 9 = 1
Step-by-step explanation:
The major axis is along the x axis and the minor axis is on the y axis.
Major axis = 2a = 5--5 =10 so a = 5 and a^2 = 25.
Similarly b^2 = 3^2 = 9.
Answer:
Step-by-step explanation:
Given the system of equations:
2x + 3y = 15
X + 3y = 0
What is x?
2x + 3y = 15
X + 3y = 0 subtract the bottom equation fron the top one
2x - x + 3y - 3y = 15 - 0 see how the 3y - 3y equates to zero
2x - x = 15
x = 15 Now for extra credit what is y?
X + 3y = 0
15 + 3y = 0
15 - 15 + 3y = 0 - 15
3y = -15
3y/3 = -15/3
y = -5
-15
-5
0
5
15
Answer:
48
Step-by-step explanation:
let s be the snowman, g be the girl, and t be the christmas tree
2s+g=24
2t+2ts=132
3t+2g=26
subtract 2 times the first equation from the third one to get
3t-4s=-22
from the second equation we can deduce
2t(1+s)=132
t(1+s)=66
t=66/(1+s)
Substitute:
3(66)/(1+s)-4s=-22
3(66)/(1+s)=4s-22
3(66)=(4s-22)(1+s)
3(66)=-18s+4s^2-22
4s^2-18s-220=0
using the quadratic formula, we get s = 10, s = -5.5.
2(10)+g=24
g=4
2t(1+10)=132
2t=12
t=6
So 2s+t*g= 20+6*4=48
you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r
