we know that
The measurement of the external angle is the semi-difference of the arcs it comprises.
so
Step 
<u>Find the measure of the arc AJ</u>
m∠BDE=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20BE%5D)
in this problem we have
m∠BDE=

substitute in the formula
=![\frac{1}{2} *[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)
=![[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)

Step 
<u>Find the measure of the arc FH</u>
m∠FGH=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20FH%5D)
in this problem we have
m∠FGH=

substitute in the formula
=![\frac{1}{2} *[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)
=![[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)

therefore
<u>the answer is</u>
the measure of the arc FH is 
The answer is about 36.9%
I just guessed and checked. 95-60= 35
So .3685×95 is the closest to equaling 35
Answer:22:2x10x10x10x10x10x10x10x10x10x10... 23:3.4x10 divided by 2.... 24:1.5x10 divided by 9...... 25:5.9x10x10x10x10x10x10x10x10x10x10.... 26: 4.8 x 10 divided by 3..... 27: 6.25x10x10x10x10x10.
Step-by-step explanation:I divide because on some of them it's a negative power so instead of multiplying I'll divide. Hope this helps
100% = 1
Because:to have 100 percent of something, you must have one whole. One whole equals 100% and the same backwards. I hope this helps!
So, the correct answer is equals =