Answer:
x ≈ 11.7
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos26° =
=
( multiply both sides by 13 )
13 × cos26° = x , then
x ≈ 11.7 ( to the nearest tenth )
Answer:
1. reflection across x-axis
2. translation 6 units to the right and 3 units up (x+6,y+3)
Step-by-step explanation:
The trapezoid ABCD has it vertices at points A(-5,2), B(-3,4), C(-2,4) and D(-1,2).
First transformation is the reflection across the x-axis with the rule
(x,y)→(x,-y)
so,
- A(-5,2)→A'(-5,-2)
- B(-3,4)→B'(-3,-4)
- C(-2,4)→C'(-2,-4)
- D(-1,2)→D'(-1,-2)
Second transformation is translation 6 units to the right and 3 units up with the rule
(x,y)→(x+6,y+3)
so,
- A'(-5,-2)→E(1,1)
- B'(-3,-4)→H(3,-1)
- C'(-2,-4)→G(4,-1)
- D'(-1,-2)→F(5,1)
Answer:
Line 4
Step-by-step explanation:
6(x+2) = 24
6x+12=24
6x=12
x=2
Answer:
S = R θ where θ is in radians
If θ = 2 pi then S = 2 pi R the circumference of the circle
θ = S / R = 9.7 / 9 = 1.08 rad
Since 1 rad = 360 / (2 pi) = 57.3 deg
the angle included = 1.08 rad * 57.3 deg/rad = 61.9 deg
Answer:
15°
Step-by-step explanation:
If CB is a diameter, the arc BKAC is a semicircle and has a degree measure of 180. If the measure of angle BCK is 20 and it is an inscribed angle, then the measure of the arc it intercepts is twice that. So arc BK measures 40 degrees. That means that arc KA has a measure that is found by subtracting arc AC and arc BK from 180. 180 - 40 - 110 = 30. If that arc is 30 and the angle that intercepts it is inscribed, then the angle measure is half the measure of the arc. So the angle is 15°