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Eddi Din [679]
3 years ago
15

What is the number of mole equivalents of H2 produced by the reaction of 1 mole equivalent of Mg (m) with H2SO4 (aq)?

Chemistry
1 answer:
Inga [223]3 years ago
8 0

Answer:

We'll have 1.00 mol H2

Explanation:

Step 1: Data given

Number of moles of Mg = 1.00 moles

Step 2: The balanced equation

Mg(s) + H2SO4(aq) → MgSO4(aq) + H2(g)

Step 3: Calculate moles of H2

For 1 mol Mg we need 1 mol H2SO4 to produce 1 mol MgSO4 and 1 mol H2

We'll have 1.00 mol H2

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You HAVE TO know that molarity (M) tells you the number of moles of a solute per Liters of solution.
M=mol/L
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What is the mass of 0.28 mole of iron?
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Answer:

Your answer should be 15.68 grams.

Explanation:

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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

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Give an example of gravitational potential
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Answer:

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