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3 years ago

If a gas is 0.8L at 900 mm Hg and 400K, what is the new pressure if the volume decreases to 0.5L and 300K?

Chemistry

1 answer:

mezya [45]3 years ago

5 0

Answer:

The new pressure of the gas is 1080 mmHg

Explanation:

The general equation provides a way to calculate the relationship between changesnp in volume, temperature and pressure of a given mass of gas.

The general gas equation is given as P1V1/T1 = P2V2/T2

Where P1 is initial pressure of gas

V1 is initial volume of gas

T1 is initial temperature of gas

P2 is final pressure of gas

V2 is final volume of gas

T2 is final temperature of gas

From the given question, P1 = 900 mmHg, V1 = 0.8 L, T1 = 400 K, P2 = ?, V2 = 0.5 L, T2 = 300 K

Making P2 subject of the general gas equations:

P2 = P1V1T2/V2T1

P2 = (900 × 0.8 × 300) / (0.5 × 400)

P2 = 1080 mmHg

Therefore, the new pressure of the gas is 1080 mmHg.

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How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal

Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

Moles H₂ -Molar mass: 2.016g/mol-:

8.76g * (1mol / 2.016g) = 4.345 moles

Moles O₂:

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>

8 0

3 years ago

Calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C

Alex Ar [27]

The heat (Q) required to raise the temp of a substance is:Q=m∗Cp∗ΔT where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
1380.72 Joules

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3 years ago

If you have a 4.6 L of gas in a piston at a pressure of 1.2 atm and compress 2p the gas until its volume is 2.6 L, what will the

Nesterboy [21]

Answer:

2.12atm

Explanation:

Boyle's Law: P1V1 = P2V2

Manipulate to solve for unknown: P2 = P1V1/V2

Substitute values: P2=(1.2atm)(4.6L)/2.6L

P2 = 2.1230769atm

Round to 3 sig figs to get 2.12atm

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3 years ago

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torisob [31]

Answer:

in the middle

Explanation:

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Please only answer if you know the actual thing, don't search it up! Are these correct? :P

makkiz [27]

Hey buddy I am here to help!

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3 years ago

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