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Marysya12 [62]
3 years ago
10

If a gas is 0.8L at 900 mm Hg and 400K, what is the new pressure if the volume decreases to 0.5L and 300K?

Chemistry
1 answer:
mezya [45]3 years ago
5 0

Answer:

The new pressure of the gas is 1080 mmHg

Explanation:

The general equation provides a way to calculate the relationship between changesnp in volume, temperature and pressure of a given mass of gas.

The general gas equation is given as P1V1/T1 = P2V2/T2

Where P1 is initial pressure of gas

V1 is initial volume of gas

T1 is initial temperature of gas

P2 is final pressure of gas

V2 is final volume of gas

T2 is final temperature of gas

From the given question, P1 = 900 mmHg, V1 = 0.8 L, T1 = 400 K, P2 = ?, V2 = 0.5 L, T2 = 300 K

Making P2 subject of the general gas equations:

P2 = P1V1T2/V2T1

P2 = (900 × 0.8 × 300) / (0.5 × 400)

P2 = 1080 mmHg

Therefore, the new pressure of the gas is 1080 mmHg.

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An ionic bond forms between a_____ & a_____?​
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At 20°C the vapor pressure of benzene (C6H6) is 75 torr, and that of toluene (C7H8) is 22 torr. Assume that benzene and toluene
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Answer: The mole fraction of benzene will be 0.34 and mole fraction of toluene is 0.66

Explanation:

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p_1=x_1p_1^0 and p_2=x_2P_2^0

where, x = mole fraction in solution

p^0 = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2\\p_{total}=x_{benzene}p_{benzene}^0+x_{toluene}P_{toluene}^0

x_{benzene}=x,

x_{toluene}=1-x_{benzene}=1-x,

p_{benzene}^0=75torr

p_{toluene}^0=22torr

p_{total}=40torr

40=x\times 75+(1-x)\times 22

x=0.34

Thus (1-x0 = (1-0.34)=0.66

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