Solubility is a function of temperature. But for this case solubility is not given at that certain temperature and it is somewhat difficult to find for certain datas. I would be using the solubility at 20 degrees celsius which is 1.85g/100g Water
.0185 g / g water = g barium hydroxide / 100 g
1.85 g of barium hydroxide can be dissolved in 100 g of water.
Hope this could help. Have a nice day.
ahí esta la respuesta espero que te sirva
2) 11.2
All you have to do is multiply 44 by 22.4 L, which equals 985.6
Then you divide 985.6 by 88 to get your answer of 11.2 L
Answer:
The answer to your question is the third option: 122.7 g of NaCl
Explanation:
Data
mass of NaCl = ?
molecular mass of NaCl = 23 + 35.5 = 58.5
volume = 0.50 l
concentration = 4.20 M
Formula

Moles = Molarity x volume
Process
1.- Substitute the data given to find the moles of NaCl
Moles = 4.20 x 0.5
Moles = 2.1
2.- Calculate the grams of NaCl using proportions
58.5 g of NaCl ----------------- 1 mol
x ---------------- 2.1 moles
x = (2.1 x 58.5) / 1
3.- Result
x = 122.7 g of NaCl