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Helen [10]
4 years ago
12

When zinc or aluminum was allowed to react with the copper sulfate , what was the limiting reagen?

Chemistry
1 answer:
musickatia [10]4 years ago
5 0
Usually it is the CuSO4 that is the limiting reagent. 

<span>if all of the color of the solution was gone, but there was still some zinc metal mixed in with the copper metal produced, then Zn is the excess reagent </span>

<span>f all of the color of the solution was not gone, but there was no zinc metal left in with the blue copper solution , then Zn is the limiting reagent Hope this helps.</span>
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How many grams of Ba(OH)2 will dissolve in 100g of water at 75 degree Celsius
netineya [11]
Solubility is a function of temperature. But for this case solubility is not given at that certain temperature and it is somewhat difficult to find for certain datas. I would be using the solubility at 20 degrees celsius which is 1.85g/100g Water

.0185 g / g water = g barium hydroxide / 100 g

1.85 g of barium hydroxide can be dissolved in 100 g of water. 

Hope this could help. Have a nice day.
3 0
3 years ago
X+KOH→CH-CH=CH 2 +KBr+H2O. What is the<br> compound represent “x”?
Andrews [41]

Answer:

I guess it is HBr

6 0
3 years ago
EJEMPLOS DE SOLUCIONES QUÍMICAS EN LA NATURALEZA
kifflom [539]

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5 0
3 years ago
If a gas has a molecular mass of 44.0, the volume of 88.0 grams of the gas at STP would be ..
Montano1993 [528]
2) 11.2
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3 0
3 years ago
How many grams of NaCl are contained in 0.50 L of a 4.20 M solution?
disa [49]

Answer:

The answer to your question is the third option: 122.7 g of NaCl

Explanation:

Data

mass of NaCl = ?

molecular mass of NaCl = 23 + 35.5 = 58.5

volume = 0.50 l

concentration = 4.20 M

Formula

Molarity = \frac{moles}{volume}

     Moles = Molarity x volume

Process

1.- Substitute the data given to find the moles of NaCl

     Moles = 4.20 x 0.5

     Moles = 2.1

2.- Calculate the grams of NaCl using proportions

     58.5 g of NaCl ----------------- 1 mol

        x                     ----------------  2.1 moles

      x = (2.1 x 58.5) / 1

3.- Result

      x = 122.7 g of NaCl      

8 0
3 years ago
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