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3 years ago

95. A 20-gallon alcohol-water solution contains 15% pure alcohol. How much alcohol should

Mathematics

1 answer:

navik [9.2K]3 years ago

4 0

Answer:

1.25 gallons of alcohol

Step-by-step explanation:

Let x represent the amount of alcohol to add to the mix. Then the total amount of alcohol in the mix is ...

0.15×20 + x = 0.20×(20 +x)

3 +x = 4 + 0.2x . . . . simplify

0.8x = 1 . . . . . . . . . . add -3-0.2x

x = 1/0.8 = 1.25 . . . . divide by 0.8

1.25 gallons of alcohol should be added to make 21.25 gallons of 20% alcohol.

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You placed a 12% down payment on a new home. Given that the amount of the down payment was $42,655.12, determine the price of th

Soloha48 [4]

Answer:

355,459.33

Step-by-step explanation:

42,655.12/12 = 3554.59

3554.59*100 = 355459.33

7 0

3 years ago

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What’s the capital of France? answer and you'll get brainly!!

Vlad [161]

Answer:

the capital of france is paris.

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3 years ago

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Mia wants to buy 3 notebooks for $1.29 each. What is the expression for the total cost?

ololo11 [35]

Step-by-step explanation:

Mia want to buy 3 notebook for $1.29 each ,

then total cost =3×1.29

hence, 3×29

1\6+1/12+2/6=2+1+4/12

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8 0

3 years ago

-8z+(4.5)+3.5z+7y-1.5

bogdanovich [222]

Answer:

$\boxed{\sf{7y+3-4.5z}}$

Step-by-step explanation:

In order to combine like terms, you have to isolate x and y from one side of the equation.

$\sf{-8z+\left(4.5\right)+3.5z+7y-1.5}$

First, thing you do is remove parentheses.

$\Longrightarrow: \sf{-8z+4.5+3.5z+7y-1.5}$

Solve.

Then, you combine like terms.

$\Longrightarrow:\sf{-8z+3.5z+7y+4.5-1.5}$

Add/subtract the numbers from left to right.

-8z+3.5z=-4.5z

Rewrite the problem down.

$\Longrightarrow: \sf{-4.5z+7y+4.5-1.5}$

Solve.

4.5-1.5=3

$\Longrightarrow: \boxed{\sf{7y+3-4.5z}}$

Therefore, the correct answer is 7y+3-4.5z.

I hope this helps, let me know if you have any questions.

6 0

2 years ago

Please help me solve this answer it all for me please

mestny [16]

Answer:

The slopes are

$m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}$

Therefore, the equations are equations of Perpendicular Lines .

Step-by-step explanation:

Given:

$y=\dfrac{2}{5}\times x + 1$ ......................Equation ( 1 )

$5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2$ ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

$y=mx+c$

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = $\dfrac{2}{5}$

Step 2.

Slope of equation 1 = m2 = $-\dfrac{5}{2}$

Step 3.

Product of Slopes = m1 × m2 = $\dfrac{2}{5}\times -\dfrac{5}{2}=-1$

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

$m1=\dfrac{2}{5},m2=-\dfrac{5}{2}$

Therefore, the equations are equations of Perpendicular Lines .

4 0

3 years ago