We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.
Upon rounding to nearest tenth, we will get:
Therefore, the length of the side IJ is approximately 258.8 units.
So,
First, we will find the surface area of the garden in feet.
(70)(45) = 3150 square ft.
Next, to find the surface area of the garden inches, we need to recall the conversion rate between feet and inches.
1 ft. = 12 in.
So, multiply 3150 by 12.
(3150)(12) = 37,800 square in.
To find the surface area of the garden in yards, we need to recall the conversion rate between yards and feet.
1 yd. = 3 ft.
So, divide 3150 by 3.
Area of the garden in inches: 37,800 square in.
Area of the garden in feet: 3150 square ft.
Area of the garden in yards: 1050 square yd.
i think the answer to this problem is49
You can eliminate fractions by multiplying the whole thing by 7.
... -x +28 ≥ 21x
Now, add x to get all x-terms on the right. Then, divide by the coefficient of x.
... 28 ≥ 22x
... 28/22 ≥ x
This fraction can be reduced, so we have ...
... A. x ≤ 14/11
Answer:
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Step-by-step explanation:
