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3 years ago

In the diagram, transversal t cuts parallel lines a and b. Which equation is necessarily true?

Mathematics

2 answers:

Svetllana [295]3 years ago

4 0

B is the correct answer

hoa [83]3 years ago

3 0

Answer:

The correct answer is option B.

m<3 = m<6

Step-by-step explanation:

From the figure we an see that, a and b are parallel lines and line t is the traversal on the lines.

<u>To find the correct option</u>

From the given figure we get

Corresponding angles are,

<1 & <5, <2&<6, <2&<7 and <4 &<8

Alternate interior angles are,

<3 & <6 and <4 &<5

Alternate interior angles are equal.

m<3 = m<6

Therefore the correct answer is optionB

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Which statements are true regarding the sides and angles<br> of the triangle? Select three options.

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Answer:

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Step-by-step explanation:

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3 years ago

If you vertically compress the absolute value parent function ?? What is the equation of the new function

Bumek [7]

Answer: Choice A -- f(x) = (1/3)*|x|

============================================

The input of a function is x and the output is y = f(x)

To vertically compress a function, we will multiply the y value by some fraction smaller than 1. This is so that the y coordinates are a fraction of what they once were.

In this case, we multiply y by 1/3 so that something that has a y coordinate of y = 81 becomes y = 27 (divide by 3)

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3 years ago

Help me with this math work please

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2 years ago

Read 2 more answers

The area of a triangle is one half the base and times the height. If the area of the triangle is 16 square inches and the vase i

sergij07 [2.7K]

Step-by-step explanation:

so, yes, the area of a triangle is

baseline × height / 2

so, we have here

16 = 8 × height / 2 = 4 × height

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8 0

2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers