Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Answer:
Step-by-step explanation:
The formula for finding the midpoint of two coordinates is expressed as;
M(X,Y) = 
Given the coordinates c(-4,5) and d(-1,-4), x1 = -4, y1 = 5, x2 = -1 and y2 = -4.
For the X coordinate of the midpoint
X = x1+x2/2
X = -4+(-1)/2
X = -4-1/2
X = -5/2
X = -2.5
Similarly for Y:
Y = y1+y2/2
Y = 5+(-4)/2
Y = 5-4/2
Y = 1/2
Y = 0.5
Hence the midpoint coordinate of C(-4,5) and D (-1,-4) is (-2.5, 0.5)
(2,3) , (0,-3) , (-2,1) are the points.
Hope this helps... Let me know if you wanna know anything.
Answer:
23. 0.4583 seconds
24. 0.0107 seconds
Step-by-step explanation:
The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.
90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s
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23. The time it takes for the ball to travel 60.5 ft is ...
time = distance/speed
time = (60.5 ft)/(132 ft/s) = 0.4583 s
It takes 458.3 milliseconds to reach home plate.
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24. time = distance/speed
time = (17 in)/(1584 in/s) = 0.0107 s
The ball is in the strike zone for 10.7 milliseconds.
I'm pretty sure the answer is 15 base-ten blocks
