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Montano1993 [528]
3 years ago
15

Can someone solve this

Mathematics
1 answer:
Natalka [10]3 years ago
4 0

Option D:

ΔCAN ≅ ΔWNA by SAS congruence rule.

Solution:

Given data:

m∠CNA = m∠WAN and CN = WA

To prove that ΔCAN ≅ ΔWNA:

In ΔCAN and ΔWNA,

CN = WA (given side)

∠CNA = ∠WAN (given angle)

NA = NA (reflexive side)

Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.

Hence option D is the correct answer.

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Find the value of angle A and angle B pls help (:
ankoles [38]

Answer:

m<A=97

m<B=97

Step-by-step explanation:

m<A=m<B

Congruent angles and they are vertical angles. The other two are also the same because the angles given have the same degrees.

m<A is supplementary to 83 degrees

Supplementary angles are two angles that sum up to 180 degrees.

180-83=97

97 degrees is the answer for each missing angles.

7 0
3 years ago
the length of a rectangle is 6.7 cm more than 2 times the width. If the perimeter of the rectangle is 57.2 cm, what are its dime
ss7ja [257]
57.2-6.7-6.7=43.8
43.8÷6=7.3
7.3×2+6.7=21.3
length = 21.3cm
width = 7.3cm
(21.3×2)+(7.3×2) = 57.2
hope that helps
6 0
3 years ago
Simplify. Help me ASAP please
Doss [256]

Answer:

option C is the correct answer my friend

8 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-4,8) and (-14.8)?
bonufazy [111]

Answer:

your answer is 0 because it's a horizontal line

3 0
3 years ago
At the bottom is a completed addition problem, with all the digits replaced by letters. Every letter represents a single digit a
Rashid [163]

Answer:

T = 5 (H = 7, M = 1); T = 7 (H = 4, M = 2); T = 9 (H = 1, M = 3)

Step-by-step explanation:

We know MH+MH+MH=TM

MH is a two digit number, and TM is also a two digit number.

MH+MH+MH=3*(MH)<100

3M<=9, meaning that M could be 1, 2, or 3.

If M=1, MH+MH+MH=3(10+H)=30+3H=TM=10*T+1

30+3H=10T+1, so 3H must include 1 in one's digit.

The only possibility is that 3H = 21, then H = 7

MH+MH+MH=17+17+17=TM=51, T = 5

If M=2, MH+MH+MH=3(20+H)=60+3H=TM=10T+2

60+3H=10T+2, so 3H must include 2 in one's digit.

The only possibility is 3H = 12, then H = 4

MH+MH+MH=24+24+24=72, T = 7

If M=3, MH+MH+MH=3(30+H)=90+3H=TM=10T+3

90+3H=10T+3, so 3H must include 3 in one's digit.

The only possibility is 3H = 3, then H =1

MH+MH+MH=31+31+31=93, T=9

4 0
3 years ago
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