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shutvik [7]
3 years ago
12

How many points need to be removed from this graph so that it will be a function?

Mathematics
1 answer:
leva [86]3 years ago
5 0
You didn't add a graph lol
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What is the first four terms in the multiplication or ,geometric , pattern in which the first term is 2 and then each term is mu
kirza4 [7]

Answer:

Sequence will be 2, 14, 98, 686.

Step-by-step explanation:

Since we know in an geometric sequence the terms are in the form are

T_{n}=a(r)^{n-1} in which

a = first term

r = common ratio

n = number of term

Now from this expression we can all terms of the sequence

in which a = 2 and common ratio r = 7

The sequence will be

2, 2.(7), 2.(7)^{2},2.(7)^{3}

Or 2, 14, 98, 686

So the answer is 2, 14, 98, 686.

7 0
4 years ago
34% of what number is 51?
LenKa [72]
34% of 150 is 51. 
I hope this helps.
3 0
3 years ago
Read 2 more answers
Each guest at casandras party had 3 turns to act out worlds during a game. They began with a list of 50 words. When they finishe
Veronika [31]

Answer:

16 fits but not evenly

Step-by-step explanation:

16 times 3 equals 48 and 17 times 3 equal is 51 so someone didnt go 3 times.

7 0
3 years ago
Pls answer this and I will mark u brailist and give u thanks
AysviL [449]
A + 3A = 120
4A = 120
A = 30
B = 90
7 0
3 years ago
Assume you are given a boolean variable named isRectangular and a 2-dimensional array that has has been created and assigned to
Savatey [412]

Answer:

nElements = 0;

for (int i = 0; i < a2d.length; i++)

nElements += a2d[i].length;

isRectangular = true;

for (int i = 1; i < a2d.length && isRectangular; i++)

if (a2d[i].length != a2d[0].length)

isRectangular = false;

Step-by-step explanation:

2 dimensional array is created and  initialize element with 0. and the taking loop for 2 dimensional array .such as

n Elements = 0;

for (int i = 0; i < a2d.length; i++)

n Elements += a2d[i].length;

A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.

If rectangular is false then  apply if statement  and see if a2d[i] is not equal to a2d[0]

if (a2d[i].length != a2d[0].length)

isRectangular = false;

4 0
4 years ago
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