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UkoKoshka [18]
3 years ago
15

PLEASE HELP IM BEING TIMED

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
4,-1 and 0,-2 I THINK
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Assume that when adults with smartphones are randomly​ selected, ​57% use them in meetings or classes. If 8 adult smartphone use
vovikov84 [41]

Answer:

≈ 0.2526

Step-by-step explanation:

<u>The number of combinations of 4 out of 8:</u>

  • 8C4 = 8!/(4!(8-4)!)= 8*7*6*5/(1*2*3*4)= 70

<u>Success factor is: </u>

  • 57% = 0.57

<u>and failure factor is: </u>

  • (100 - 57)%= 43%= 0.43

<u>Probability:</u>

  • 0.57⁴*0.43⁴*70 ≈ 0.2526
6 0
3 years ago
What is the value of x + 3y + z if x = 4, y = 5, and z= 22<br>a) 16<br>b) 41<br>c) 2​
fgiga [73]

Answer:

OPTION B - 41

Step-by-step explanation:

An expression is given and the corresponding values for the expression are also given. We have to substitute the given values to arrive at the answer.

The given expression is:   x + 3y + z.

Also given: x = 4, y = 5, z = 22.

Substitute these values in the above expression, we get:

4 + 3(5) + 22 = 4 + 15 + 22 = 41.

∴                                       x + 3y + z = 41

3 0
3 years ago
Share successful learning strategies that you have applied in previous mathematic courses
marshall27 [118]
Sure, I have this strategy to make a sheet with questions of that chapter and do that before I study the chapter so I can see if I know a little or a lot of that chapter
5 0
2 years ago
1.1.31
miv72 [106K]

Answer:yes

  • Step-by-step explanation:well its just yes so your welcome

7 0
3 years ago
Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2
Crank
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>

---------------------------------------------------------------------

6x^2y − 3xy − 24xy^2 + 12y^2

Apply exponent rule:

6x^2y-3xy-24xyy+12yy

Rewrite 12 as 4*3

Rewrite -24 as 8*3

Rewrite 6 as 2*3

2*3x^2y-3xy+8*3xyy+4*3yy

Factor out common term 3y:

3y(2x^2-x-8xy+4y)

Factor 2x^2-x-8xy+4y:

3y(2x-1)(x-4y)

Your Answer Is 3y(2x-1)(x-4y)

plz mark me as brainliest if this helped :)

8 0
3 years ago
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