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7nadin3 [17]
3 years ago
5

Solve –4(6x + 3) = –12(x + 10). A. x = 2 B. x = 9 C. x = 5 D. x = –5

Mathematics
1 answer:
sergey [27]3 years ago
6 0
–4(6x + 3) = -12<span>(x + 10)
</span><span> -24x - 12 = -12x - 120
12x = 108
x = 9

answer
</span><span>B. x = 9</span><span>

</span>
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What is average of 39, 43, 28, 36, and 29?<br><br> A. 30<br> B. 35<br> C. 40<br> D. 175
elena-s [515]
To find the average, find the mean: add all the numbers together and divide by the number there is.

First add all the numbers together:
39 + 43 + 28 + 36 + 29 = 175

Next, divide 175 (the total) by 5 (because there are 5 numbers)

175/5 = 35

35 is your average.

hope this helps
3 0
3 years ago
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The base of a triangle exceeds the height by 3 cm if the area is 170 cm² what is the length of the base and the height of the tr
Strike441 [17]

Hey there!!

How do we find the area of a triangle?

Ans - Formula = ( 1 / 2 ) ( base ) ( height )

In the question, it states the base exceeds the height by 3 cm

Let's take the height as ' x '

The, the base of the triangle would be ' x + 3 '

It's area = 170 cm²

Let' get this into an equation :

( 1/2 ) ( x ) ( x + 3 ) = 170

... ( x / 2 ) ( x + 3 ) = 170

... ( x² + 3x / 2 ) = 170

Multiplying by 2 on both sides

... x² + 3x = 340

Subtract 340 on both sides

... x² + 3x - 340 = 0

We can write this as

... x² - 17x + 20x - 340 = 0

... x ( x - 17 ) + 20 ( x - 17 ) = 0

... ( x + 20 ) = 0

... ( x - 17 ) = 0

... x = -20

... x = 17

As the value can not be in negatives, we take x as 17

The value of height = 17 cm

The value of the base = 20 cm

Hope my answer helps!!


6 0
3 years ago
Read 2 more answers
The length of the hypotenuse of a right triangle is 16 inches. If the length of one leg is 5 inches, what is the approximate len
Temka [501]
About 15 inches- by pythag- \sqrt{16^{2} - 5^{2} }
6 0
3 years ago
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For the data in the table, write an equation for the direct variation.
melisa1 [442]

The equation of direct variation is,

\begin{gathered} y=kx \\ k=\frac{y}{x} \end{gathered}

Substitute the values of <em>y</em> and <em>x</em>.

\begin{gathered} k=\frac{5.4}{4} \\ k=1.35 \end{gathered}

So, the obtained equation will be <em>y</em>=1.35(x).

Let's check with the values of <em>x</em>.

1) If <em>x</em>=4

\begin{gathered} y=1.35x \\ y=1.35(4) \\ y=5.4 \end{gathered}

2) If <em>x</em>=2

\begin{gathered} y=1.35x \\ y=1.35(2) \\ y=2.7 \end{gathered}

3) If <em>x</em>=-2

4 0
1 year ago
There are 20 students in my class. Each student needs: .2 cups, 2 plates, 1 party hat and a pair of earphones. My teacher has 2
garik1379 [7]

Answer:

Simple, no. This would not be enough.

Step-by-step explanation:

This is because you mentioned that there are 20 students and each of them needed 2 plates. So, there would need to be at least 40 plates. Forks seem irrelevant in this question but if the teacher has 8 plates in 1 box and another 8 in the second box, that would sum up to 16 plates that are available. And the fact that the box doesn't even include the other items, should hint the lack of items available for the students.

This question seemed worded differently. But tried my best. :)

8 0
3 years ago
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