Answer:
G). 1.2x + 7.92 -3.3x = 41
-2.1x=33.08
x = 33.08/-2.1
x = - 15.752
H). 3x/2 + 9/5 = 12
Multiply through by 10
15x + 18 =120
15x =120-18
15x = 102
x =102/15
x=34/5
I). 5 = 9/4 - r/3
Multiply through by 12
60= 27 - 4r
60 - 27 = -4r
33 = - 4r
r = -33/4
J). 2(x - 2) = 12
2x - 4 = 12
2x = 16
x = 16/2
x = 8
Given three grids with each grid representing one whole.
Each grid represents 1 ones and each vertical bar of a grid represent 1 tenth.
There are 10 vertical bars in each grid, hence each grid represent 1 ones = 10 tenths and 2 grids represent 2 ones = 20 tenths.
Therefore, two complete grids are to be shaded to <span>show that 2 ones is the same as 20 tenths</span>
Answer:
0.03333
Step-by-step explanation:
Given that there are three machines. All of the machines can produce 1000 pins at a time.
Chance for any machine is thus equaly likely = 1/3
The rate of producing a faulty pin from Machine 1 be 10%, from Machine 2 be 20% andfrom Machine3 be 5%.
Machine I II III total
Faulty 0.10 0.20 0.05
Prob 0.3333 0.3333 0.3334 1
Faulty*prob 0.03333 0.06666 0.16665 0.26664
Thus probability that a produced pin will be faulty and it will be from the firstmachine
= 0.03333
What's a divisability table are you. B or a g how old
Answer:
C. 30
Step-by-step explanation:
-It is a statistical rule of thumb that the size of a sample must be 
.
-This size is deemed adequate for the Central Limit Theorem to hold.
-At this size or greater, the shape of the resultant distribution is normal.
#It should however be noted, that for a normal distribution the CLT holds even for smaller sample sizes.
