Given : <span>Triangle fgh is inscribed in circle o </span> oh = 6 = radius of the circle <span>∵ fh is congruent to og </span> <span>∴ fh = og = radius og the circle = 6 </span> <span>∵ of = radius of the circle = 6 </span> <span>∴ oh = fh = of = radius of the circle = 6 </span> ∴ Δ foh is Equilateral Triangle
<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle </span> ∵ total area of the circle = π r² and total central angle of the circle = 360° ∴ Area of sector foh = (60°/360°) * π r² ∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85
The answer is:
<span>the area of the sector formed by angle foh
= 18.85</span>
