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Valentin [98]
3 years ago
14

Triangle fgh is inscribed in circle o the length of radius oh is 6 and fh is congruent to og. what is the area of the sector for

med by angle foh
Mathematics
1 answer:
Vilka [71]3 years ago
4 0
Given :
<span>Triangle fgh is inscribed in circle o
</span>
oh = 6 = radius of the circle 
<span>∵ fh is congruent to og
</span>
<span>∴ fh = og = radius og the circle = 6
</span>
<span>∵ of = radius of the circle = 6
</span>
<span>∴ oh = fh = of = radius of the circle = 6
</span>
∴ Δ foh is Equilateral Triangle

<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle
</span>
∵ total area of the circle = π r²  and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85

The answer is:

<span>the area of the sector formed by angle foh  = 18.85</span>
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